KONVERZIJE BROJNIH SISTEMA
Zadaci (156) 10 =( )2 (10101000011 )2 = ( ) 10 100111000 156 : 2 = 78 39 32 19 9 4 1 1347 (10101000011 )2 = = 1*20+1*21+1*26+1*28+1*210 = 1+2+64+256+1024=1347
(1016) 10 =( )8 (508) 10 =( )16 (11250) 10 =( )16 1770 1016:8=127:8=15:8=1 0 7 7 1FC 508:16=31:16=1 12 15 2BF2
(10110011010001010)2 = ( )8 (10001111010001110)2 = ( )8 (10110011010001010)2 = ( )16 (10001111010001110)2 = ( )16
Heksadecimalni u oktalni Preko binarnog brojnog sistema. (A3)16 = ( )8
(A3)16 = ( )2 = ( )8 (A3)16 =(1010 0011)2 3 : 2= 1 (3)16 = (11 )2 10 : 2= 1 (3)16 = (11 )2 10 : 2= 5 2 1 (A)16 = (1010 )2
(A3)16 = ( )2 = ( )8 (A3)16 =(1010 0011)2 = (10 100 011)2 (011)2 = 0*22+1*21+1*20=2+1=3 (100)2 = 1*22+0*21+0*20=4 (010)2 = 0*22+1*21+0*20=2 (A3)16 =(1010 0011)2 = (10 100 011)2 = = ( 2 4 3)8
Heksadecimalni u oktalni (F5A)16 = ( )2= ( )8 (7D4)16 = ( )2= ( )8 (6CE)16 = ( )2= ( )8